1.

Equilibrium constants K_1 and K_2 for the following equilibria (a) NO_((g)) + 1/2 O_(2(g)) hArr NO_(2(g)) (b) 2NO_(2(g)) hArr 2NO_((g)) + O_(2(g))are related as :

Answer»

`K_(2)=(1)/(K_(1))`
`K_(2)=(K_(1))/(2)`
`K_(2)=(1)/(K_(1)^(2))`
`K_(2)=K_(1)^(2)`

SOLUTION :`K_(1)=([NO_(2)])/([NO][O_(2)]^(1//2))`
and`K_(2)=([NO]^(2)[O_(2)])/([NO_(2)])=(1)/(K_(1)^(2))`
`THEREFORE K_(2)=(1)/(K_(1)^(2))`


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