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Equimolar mixture of two gases A_(2) and B_(2) is taken in a rigid vessel at temperature 300 K. The gases reacts according to given equations : A_(2)(g)hArr2 A (g)K_(P1)=? B_(2)(g)hArr2 B (g)K_(P2)=? A_(2)(g)+B_(2)(g)hArr2 AB (g)K_(P3)=2 If the initial pressure in the container was 2 atm and final pressure developed at equilibrium is 2.75 atm. in which equilibrium partial pressure of gas AB was 0.5 atm, calculate the ratio of (K_(P2))/(K_(P1)) [Given : Degree of dissociation of B_(2) is greater than A_(2)]. |
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Answer» 8 |
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