InterviewSolution
Saved Bookmarks
| 1. |
Equivalent conductance of 1 M propanoic acid is 10 `ohm^(-1)" cm^(2)eq^(-1)`. pH of the propanpoic acid solution isA. 7B. `3.3`C. `1.3`D. `6.8` |
|
Answer» Correct Answer - C `alpha=(^^_(eq)^(c))/(^^_(eq)^(0))=(10)/(200)=0.05` `[H^(+)]=C alpha =1xx0.05=0.05` `pH=-log[H^(+)]=-log(5xx10^(-2))` `=2 log 10 - log 5 =`2-0.6990=1.3` |
|