1.

Equivalent conductance of saturated BaSO_4 is 400 ohm^(-1) cm^(2) "equiv"^(-1) and specific conductance is8 xx 10^(-5) ohm^(-1), cm^(-1) . Hence K_(sp) of BaSO_4is

Answer»

`4 XX 10^(-8) M^(2) `
`1 xx 10^(-8) M^(2)`
`2 xx 10^(-4) M^(2)`
`1 xx 10^(-4) M^(2)`

SOLUTION :`^^_(EQ) = (K xx 1000)/(N^(0)) , N = (8 xx 10^(-5) xx 1000)/(400) = 2 xx 10^(-4) N`
` S = M = (N)/(2) = (2 xx 10^(-4))/(2) = 10^(-4) M , K_(sp) = S^(2) = (10^(-4))^(2) = 10^(-5)`


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