1.

Equivalent conductivity at infinite dilution for sodium- potassium oxalate ((COO^(-))_2 Na^(+)K^(+)) will be [ Given molar conductivities of oxalate, K^(+) and Na^(+) ions at infinite dilution are 148.2, 50.1, 73.5 S cm^(2) mol^(-2) respecitively '

Answer»

`271.8 S cm^(2) eq^(-1)`
`67.95 S cm^2 eq^(-1)`
`543.6 S cm^(2) eq^(-1)`
`135.9 cm^(2) eq^(-1)`

SOLUTION :`lambda_(m)^(oo) = lambda_(m("oxalate"))^(oo) + lambda^(m(NA^+))^(oo) + lambda_(m(K^+))^(oo)`
`lambda^(m)^(oo) =(148.2 + 50.1+73.5)S cm^(2) mol^(-1)`
`lambda_(m)^(oo) =271. 8Scm^(2) mol^(-1)`
`therefore lambda_(eq)^(oo) = (271.8)/(2) = 135.8 S cm^(2) eq^(-1)((lambda_(eq)^(oo) = (lambda_m)^(oo))/("N. factor"))`


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