1.

Equivalent conductivity at infinite dilution for sodium potassium oxalate (COO^(-))_(2)Na^(+)K^(+) will be [given, molar conductivities of oxalate, K^+ and Na^(+) ions at infinite dilution are 148.2, 50.1, 73.5 S cm^(2)mol^(-1), respectively]

Answer»

`271.8cm^(2)eq^(-1)`
`67.95S" "cm^(2)eq^(-1)`
`543.6S" "cm^(2)eq^(-1)`
`135.9S" "cm^(2)eq^(-1)`

Solution :`lamda_(M)^(OO)=lamda_(M)^(oo)("Oxalate")+lamda_(M)^(oo)(NA^(+))+lamda_(M)^(oo)(K^(+))`
`lamda_(M)^(oo)=(148.2+50.1+73.5)S" "cm^(2)mol^(-1)`
`lamda_(M)^(oo)=271.8S" "cm^(2)mol^(-1)`
`thereforelamda_(Eq)^(oo)=(271.8)/(2)=135.9S" "cm^(2)eq^(-1)(lamda_(eq)^(oo)=(lamda_(M)^(oo))/("N. factor"))`


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