1.

Equivalent conductivity at infinite dilution for sodium potassium oxalate, (COO^(-))_(2)Na^(+)K^(+), will be (given, molar conductivities of oxalate, K^(+) and Na^(+) ions at infinite diluton are 148.2,50.1,73.5" S "cm^(2)mol^(-1) respectively).

Answer»

`271.8" S "cm^(2)eq^(-1)`
`67.96" S "cm^(2)eq^(-1)`
`543.6" S "cm^(2)eq^(-1)`
`135.9" S "cm^(2)eq^(-1)`.

Solution :`wedge_(m)^(@)` (Sod. Pot. Oxalate)`=lamda_(m)^(@)(Na^(+))+lamda_(m)^(@)(K^(+))+lamda^(2)`(oxalate)
`=(50.1+73.5+148.2)" S "cm^(2)MOL^(-1)`
`=271.8" S "cm^(2)mol^(-1)`
`wedge_(eq)^(@)=(wedge_(m)^(@))/("TOTAL chrge on cations or ANIONS (n factor)")`
`=(271.8)/(2)=135.9" S "cm^(2)eq^(-1)`.


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