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Equivalent conductivity of acetic acid at infinite dilution is 39.7 and for 0.1 M acetic acid the equivalent conductance is "5.2 mho.cm"^(2)."gm.equiv."^(-1). Calculate degree of dissociation, H^(+) ion concentration and dissociation constant of the acid. |
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Answer» Solution :`ALPHA=(lambda_(C ))/(lambda_(oo))=0.01333=1.33%` `{:(CH_(3)COOHhArrH^(+)+CHCOO^(-)),(C(1-alpha)""Calpha""Calpha):}` `therefore[H^(+)]=Calpha=0.1xx0.0133=0.00133M` `K=(alpha^(2)C)/(1-alpha)=(0.0133^(2)xx0.1)/((1-0.0133))=2.38xx10^(-5)M` |
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