1.

Equivalent weight of MnO_(4)^(-) in acidic, weakly basic and neutral medium are in the ratio of

Answer»

`3:5:15`
`5:3:1`
`5:1:3`
`3:5:5 `

SOLUTION :Acdic medium
` MnO_(4)^(- )+8H^(+)+5E^(- )to Mn^(2+) +4H_ 2O`
Weaklybasicmedium:
`MnO_(4)^(- )+ 2H_2 O+3e^(- )toMnO_2+4 OH^(-) `
Neutralmedium: `MnO_(4)^(- )+2H_2O+3e^(-)toMnO_2+4OH^(-)`
ifM isthe MOLECULARWEIGHTOF `KMnO_4 `then its equivalentweight inacidic. acidicbasicand neutralmediarespectivelyare :
`M/5 :M/3 :M/3or3 :5:5`


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