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Equivalentconductance of BaCI_(2), H_(2)SO_(4) and HCIare x_(1)x_(2) and x_(3) S cm^(2) "equiv"^(-1)atinfinitedilution if specific conductance of saturated BaSO_(4)solutionis of y S cm d^(-1) then k_("SP") of BaSO_(4) is |
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Answer» `(10^(3)y)/(2(x_(1)+x_(2)-2x_(3))` `wedge_(BaSO_(4))^(@)=(1000xx"specific conductance")/("solubility" ("in SATURATED solution" ))` `X_(1)+x_(2)-2x_(3)=(1000Y)/("solubility")` `therefore`solubility `(BaSO_(4))=(1000y)/(x_(1)+x_(2)-2x_(3))N=(1000y)/(2(x_(1)+x_(2)-2x_(3))M` `K_(SP)(BaSO_(4))=[Ba^(2+)][SO_(4)^(2-)]M^(2)=(10^(6)y^(2))/(4(x_(1)+x_(2)-2_(3))^(2)` |
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