InterviewSolution
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InterviewSolution
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Escape velocity of a body `1 kg` mass on a planet is `100 ms^(-1)`. Gravitational potential energy of the body at that planet isA. 5000JB. `-5000J`C. `-2400J`D. `-1000J` |
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Answer» Correct Answer - B Escape velocity `(v_(e ))=sqrt((2GM)/(R )) " " therefore v_(e )^(2)=(2GM)/(R )` `therefore (GM)/(R )=(v_(e )^(2))/(2)" "` ……(1) and gravitational P.E. (U) `=-((GM)/(R ))m` `=-((v_(e)^(2))/(2))m " "` …. From (1) `therefore U=-((100xx100)/(2)xx1)=-5000 J` |
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