Estimate the adiabatic flame temperature of a slit lamp from the following data. C_(2)H_(5)OH(l) + 3O_(2)(g) to 2CO_(2)(g) + 3H_(2)O(g) DeltaH_(298) = 1370 kJ mol^(-1) C_(P) for (i) CO_(2) (g) = 36.43 JK^(-1) mol^(-1) , (ii) H_(2)O(g) = 33.70 JK^(-1) and(iii) N_(2)(g) = 294.4 JK^(-1) "mol"^(-1) if the above reaction is carried out in air consisting of 80% N_(2) and 20% of O_(2) by volume, what would be the final temperature?

Estimate the adiabatic flame temperature of a slit lamp from the follo

1.	Estimate the adiabatic flame temperature of a slit lamp from the following data. C_(2)H_(5)OH(l) + 3O_(2)(g) to 2CO_(2)(g) + 3H_(2)O(g) DeltaH_(298) = 1370 kJ mol^(-1) C_(P) for (i) CO_(2) (g) = 36.43 JK^(-1) mol^(-1) , (ii) H_(2)O(g) = 33.70 JK^(-1) and(iii) N_(2)(g) = 294.4 JK^(-1) "mol"^(-1) if the above reaction is carried out in air consisting of 80% N_(2) and 20% of O_(2) by volume, what would be the final temperature?
Answer» Solution :The expression of adiabatic flame temperature is `T_(1) = (DeltaH)/(C_(p)("products"))/(2 xx 36.43 + 3 xx 33.70) + 298` `=7875 + 298 = 8173` K If the reaction is carried out in air, the CONSUMPTION of 3 MOL of `O_(2)` would leave 12 mol of `N_(2)` from air. Hence, `T_(1) = (1370 xx 10^(3))/(2 xx 36.43 + 3 xx 33.70 + 12 xx 29.4) + 298 = 2600 + 298 = 2899 K`