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Estimate the fastest bit rate capable of being carried by light of wavelength 1.3 mu m. How many phone calls could be carried at this bit rate ? Band width of optical fibre = 2 GHz. |
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Answer» `2.9xx10^(7)` `v=(c)/(lambda)=(3xx10^(9))/(1.3xx10^(-6))=2.3xx10^(14)Hz` Max bit rate `=2U=2xx2.3xx10^(14)=4.6xx10^(14)Hz` For optical fibre, band width =2GHZ=`2XX10^(2)Hz` `therefore` No. of PHONE calls `=(4.6xx10^(14))/(2xx10^(4))=2.3xx10^(3)` |
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