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Estimate the temperature range for which the following standard reaction is product-favoured. SiO_(2)(s)+2C(s)+2Cl_(2)(g) to SiCl_(4)(g)+2CO(g) DeltaH^(0)=+32.9"kJ/mole and"DeltaS^(0)=226.5"J/mole.K" |
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Answer» SOLUTION :In this problem the factor `DeltaS^(@)` being positive is favourable to spontaneity, whereas the factor `DeltaH^(@)` being positive is unfavourable. Thus the REACTION becomes product-favoured above some temperature. We can SET `DeltaG^(@)` equal to ZERO in the equation `DeltaG^(@)=DeltaH^(@)-TDeltaS^(@)` and the solve for the temperature at which the reaction is at equilibrium and above which the reaction becomes product favoured as then `DeltaG^(@)` becomes NEGATIVE. `T=(DeltaH^(@))/(DeltaS^(@))=(+32.9)/(+0.2265)=145.25K` |
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