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Estimatethe mass ofcopper metalproducedduringthepassage of5 AcurrentthroughCuSO_(4) solutionfor 100minutes.Themolarmass of Cu is63.5 g mol^(-1) |
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Answer» Time = t = 100 min= 100 `xx 60 s= 6000 s ` MOLARMASS ofCu =Atomicmass ofCu =63.5g `mol^(-1)` MASS ofcu deposited= ? Reduction halfreactionat cathode . `Cu_((AG))^(++)+ 2e^(-)to Cu_((s))` Quantityof electricity`= Q=I xx t = 5 xx6000 =3000 C` Numberof molesof electrons PASSED`= (Q)/(F ) ` `= (3000)/(96500)"mol"` ` C "mol"^(-1)` `= 0.3109 "mol"` Fromthe halfreductionreaction1 molof Cu isformedby thepassageof 2 molesof electrons. Molarratioof Cu `= ("Molarof Cuformed" )/("Number ofmolesof electron" ) ` `= (1 " mol " ) /(2" mol " ) =0.5 ` Numberof molesof Cuformed = Numberof molesof electrons passed`xx ` Moleratio `= 0.3109xx 0.5= 0.1554` mol Mass ofCuformed= Molesof Cuformed`xx`MolarMass of Cu `= 0.1554 xx 63.5 = 9.87 g` |
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