1.

Ethanal and propanone undergoes aldol condensation reaction inpresence of dilute alkali to form

Answer»

`CH_(3)C(OH)(CH_(3))CH_(2)CHO`
`CH_(3)CH(OH) CH_(2)COCH_(3)`
`CH_(3)COC(OH)(CH_(3))_(2)`
`CH_(3)COCH(CH_(3))CH_(2)OH`

Solution :When aldehydes condenses with KETONE, produces four condensation products. It is the `ALPHA`- hydrogen atom of the ketone which is involved in the condensation reaction and produces MAJOR product.
`CH_(3)CHO + HCH_(2)COCH_(3) overset("dil.NaOH") to underset(" 4- hydroxy 2- pentanone")(CH_(3)CH(OH) CH_(2)COCH_(3))`


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