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Ethylene glycol is used as antifreeze in a cold climete. Mass of ethylene glycol which should be added to 4 kg of water = 1.86 K kg mol^(-1), molar mass of ethylene glycol = 62 g mol,^(-1) ) |
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Answer» 804.32 g `=((62h MOL^(-1))xx(6K)xx(4KG))/((1.86"K kg" mol^(-1)))=800 g` |
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