1.

Ethylene glycol is used as antifreeze in a cold climete. Mass of ethylene glycol which should be added to 4 kg of water = 1.86 K kg mol^(-1), molar mass of ethylene glycol = 62 g mol,^(-1) )

Answer»

804.32 g
204.30 g
400.-- g
304.60 g

Solution :`W_(B)=(M_(B)xxDeltaT_(f)xxW_(A))/K_(f)`
`=((62h MOL^(-1))xx(6K)xx(4KG))/((1.86"K kg" mol^(-1)))=800 g`


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