1.

Evaluate 10.05x10.03 by using suitable identity

Answer»

(10+0.5)²*(10+0.3)²
(100+0.25+10)*(100+0.09+6)
(110.25)*(106.09)
or
(10.04+0.01)*(10.04-0.01)......(a+b)(a-b)=a²-b²
100.0016-0.0001
=100.0015



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