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Evaluate |A|^2-5|A|+1, if A=\(\begin{bmatrix}7&4\\5&5\end{bmatrix}\)(a) 161(b) 251(c) 150(d) 151I have been asked this question in an internship interview.This interesting question is from Determinant in section Determinants of Mathematics – Class 12

Answer»

Right answer is (d) 151

The best I can explain: GIVEN that, A=\(\begin{BMATRIX}7&4\\5&5\end{bmatrix}\)

|A|=(7(5)-5(4))=35-20=15

|A|^2-5|A|+1=(15)^2-5(15)+1=225-75+1=151.



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