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Evaluate \(\begin{vmatrix}\sqrt{3}&\sqrt{2}\\-1&2\sqrt{3}\end{vmatrix}\).(a) 6-3\(\sqrt{2}\)(b) 6-\(\sqrt{2}\)(c) 6+3\(\sqrt{2}\)(d) 6+\(\sqrt{2}\)This question was addressed to me in an online quiz.This question is from Determinant in portion Determinants of Mathematics – Class 12

Answer» CORRECT answer is (d) 6+\(\sqrt{2}\)

To explain: ∆=\(\begin{vmatrix}\sqrt{3}&\sqrt{2}\\-1&2\sqrt{3}\END{vmatrix}\)

∆=(\(\sqrt{3}\)×2\(\sqrt{3}\))+\(\sqrt{2}\)

∆=6+\(\sqrt{2}\).


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