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Evaluate how many lines there are in a true ratational spectrum of CO milecules whose natural vibration frequency is omga= 4.09.10^(14)s^(-1) and moment of inertial I= 1.44.10^(39)g,cm^(2). |
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Answer» Solution :We PROCEED as above. CALCULATING `(2Iomega(0))/( ħ)` we get `(2I omega_(0))/( ħ)~= 1118` Now this must equal `J(J+1)~~(J+(1)/(2))^(2)` Taking the square root we get `J ~~33` |
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