InterviewSolution
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InterviewSolution
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Evaluate:(i) \(5^{-2}\)(ii) \((-3)^{-2}\)(iii) \((\frac{1}{3})^{-4}\)(iv) \((\frac{-1}{2})^{-1}\) |
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Answer» (i) \(5^{-2}\) ⇒ \(\frac{1}{5^{8}}\)=\(\frac{1}{25}\)[Using \(a^{-n}=\frac{1}{a^{n}}\) ;\(a^{n}=a\times a........n\, times\)] (ii) \((-3)^{-2}\) ⇒ \((\frac{1}{-3})^{2}\)=\(\frac{1}{-3}\times \frac{1}{-3}\)=\(\frac{1}{9}\)[Using \(a^{-n}=\frac{1}{a^{n}}\) ;\(a^{n}=a\times a........n\, times\)] (iii) \((\frac{1}{3})^{-4}\) ⇒ \((\frac{3}{1})^{4}\)=\(3^{4}\)=81[Using \(a^{-n}=\frac{1}{a^{n}}\) ;\(a^{n}=a\times a........n\, times\)] (iv) \((\frac{-1}{2})^{-1}\) ⇒ \(\frac{-2}{1}\)= -2[Using \(a^{-n}=\frac{1}{a^{n}}\) ;\(a^{n}=a\times a........n\, times\)] |
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