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Evaluate:`int(secx)/(log(secx+tanx)dx` |
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Answer» `d/dx[log(secx+tanx)]=1/(sex+tanx)(secxtanx+sec^2x)` `=(secx+tanx)/(secx+tanx)` `=secx` `intsecx/(log(secx+tanx))dx=int(d[log(secx+tanx)])/log(secx+tanx)` `=log[log(secx+tanx)]+c`. |
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