1.

Evaluate:`int(secx)/(log(secx+tanx)dx`

Answer» `d/dx[log(secx+tanx)]=1/(sex+tanx)(secxtanx+sec^2x)`
`=(secx+tanx)/(secx+tanx)`
`=secx`
`intsecx/(log(secx+tanx))dx=int(d[log(secx+tanx)])/log(secx+tanx)`
`=log[log(secx+tanx)]+c`.


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