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Evaluate:`int(sin2x)/(sin5xsin3x)dx` |
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Answer» `(sin2x)/(sin5xsin3x)=(sin(5x-3x))/(sin5xsin3x)` `=(sin5xcos3x-cos5xsin3x)/(sin5xsin3x)` `=(sian5xcos3x)/(sin5xsin3x)-(cos5xsin3x)/(sin5xsin3x)` `=cot(3x)-cot(5x)` `int(sin2x)/(sin5xsin3x)dx=int[cot3x-cot5x]dx` `=1/3log|sin3x|-1/5log|sin5x|+c`. |
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