1.

Evaluate:`int(sin2x)/(sin5xsin3x)dx`

Answer» `(sin2x)/(sin5xsin3x)=(sin(5x-3x))/(sin5xsin3x)`
`=(sin5xcos3x-cos5xsin3x)/(sin5xsin3x)`
`=(sian5xcos3x)/(sin5xsin3x)-(cos5xsin3x)/(sin5xsin3x)`
`=cot(3x)-cot(5x)`
`int(sin2x)/(sin5xsin3x)dx=int[cot3x-cot5x]dx`
`=1/3log|sin3x|-1/5log|sin5x|+c`.


Discussion

No Comment Found

Related InterviewSolutions