1.

Evaluate `lim_(x to oo) (sinx^(0))/(x).`

Answer» Correct Answer - `pi//180`
`underset(xto0)lim(sinx^(@))/(x)=underset(xto0)lim("sin"(pix)/(180))/(x)=(pi)/(180)" "{becausex^(@)=(pix)/(180)" radian"}`


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