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Evaluate `lim_(xto2) (x^(2)-5x+6)/(x^(2)-4).` |
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Answer» When`x=2,` the expression `(x^(2)-5x+6)/(x^(2)-4)` assumes the indeterminate form `0/0.` Here, (x-2) is a common factor in numerator and denominator. Factorizing the numerator and denominator, we have `underset(xto2)lim(x^(2)-5x+6)/(x^(2)-4)=underset(xto2)lim((x-2)(x-3))/((x+2)(x-2))` `=underset(xto2)lim(x-3)/(x+2)=(2-3)/(2+2)=-(1)/(4)` |
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