Evaluate `lim_(xtooo) 2^(x-1)tan((a)/(2^(x))).`

1.	Evaluate `lim_(xtooo) 2^(x-1)tan((a)/(2^(x))).`
Answer» Since, `underset(xtooo)lim(a)/(2^(x))=0,` we have `underset(xtooo)lim2^(x-1)tan((a)/(2^(x)))" "`(`ooxx0` form) `=underset(xtooo)lim(a)/(2).tan((a)/(2^(x)))/(((a)/(2^(x))))" "`(0/0 from)`=a/2xx1=a/2`

Discussion

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