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Evaluate the following:(i) sin 78° cos 18° – cos 78° sin 18° (ii) cos 47° cos 13° – sin 47° sin 13°(iii) sin 36° cos 9° + cos 36° sin 9° (iv) cos 80° cos 20° + sin 80° sin 20° |
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Answer» (i) As we know that sin (A – B) = sin A cos B – cos A sin B sin 78° cos 18° – cos 78° sin 18° = sin(78 – 18)° = sin 60° = √3/2 (ii) As we know that cos A cos B – sin A sin B = cos (A + B) cos 47° cos 13° – sin 47° sin 13° = cos (47 + 13)° = cos 60° = 1/2 (iii) As we know that sin (A + B) = sin A cos B + cos A sin B sin 36° cos 9° + cos 36° sin 9° = sin (36 + 9)° = sin 45° = 1/√2 (iv) As we know that cos A cos B + sin A sin B = cos (A – B) cos 80° cos 20° + sin 80° sin 20° = cos (80 – 20)° = cos 60° = 1/2 |
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