Evaluate the following limit :\(\lim\limits_{\text x \to \infty}\cfrac

1.	Evaluate the following limit :\(\lim\limits_{\text x \to \infty}\cfrac{3\text x^3-4\text x^2+6\text x-1}{2\text x^3+\text x^2-5\text x+7}\)lim(x→∞) (3x3 - 4x2 + 6x - 1)/(2x3 + x2 - 5x + 7)
Answer» Given:\(\lim\limits_{\text x \to \infty}\cfrac{3\text x^3-4\text x^2+6\text x-1}{2\text x^3+\text x^2-5\text x+7} \) Hence,\(\lim\limits_{\text x \to \infty}\cfrac{3\text x^3-4\text x^2+6\text x-1}{2\text x^3+\text x^2-5\text x+7} \)=\(\cfrac32\)

Evaluate the following limit :\(\lim\limits_{\text x \to \infty}\cfrac{3\text x^3-4\text x^2+6\text x-1}{2\text x^3+\text x^2-5\text x+7}\)lim(x→∞) (3x3 - 4x2 + 6x - 1)/(2x3 + x2 - 5x + 7)

Answer»

Given:\(\lim\limits_{\text x \to \infty}\cfrac{3\text x^3-4\text x^2+6\text x-1}{2\text x^3+\text x^2-5\text x+7} \)

Hence,\(\lim\limits_{\text x \to \infty}\cfrac{3\text x^3-4\text x^2+6\text x-1}{2\text x^3+\text x^2-5\text x+7} \)=\(\cfrac32\)