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EvaluateSin 50°/cos40 +cosec 40/sec50 - 4cos 50 cosec 40​

Answer»

e!!•sin50/cos 40 +COSEC 40/ sec50 -4cos50 cosec 40=>cos(90-50)/cos 40 +sec(90-40)/sec 50 -4 cos 50 sec( 90- 40) since cos (90-X) =sinx , sec(90-x)=COSECX=>cos40/cos40 +sec 50/sec50 -4 cos 50 sec50=>1+1-4 since cos x sec x=1=> -2....✌️❤️



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