Every time attribute A appears, it is matched with the same value of attribute B, but not the same value of attribute C. Therefore, it is true that:(a) A -> B(b) A -> C(c) A -> (B,C)(d) (B,C) -> AI have been asked this question by my college director while I was bunking the class.Asked question is from Normalization in chapter Planning Oracle Applications of Oracle

Every time attribute A appears, it is matched with the same value of a

1.	Every time attribute A appears, it is matched with the same value of attribute B, but not the same value of attribute C. Therefore, it is true that:(a) A -> B(b) A -> C(c) A -> (B,C)(d) (B,C) -> AI have been asked this question by my college director while I was bunking the class.Asked question is from Normalization in chapter Planning Oracle Applications of Oracle
Answer» The correct choice is (a) A -> B To explain I WOULD say: TRANSITIVITY rule: Same as transitive rule in ALGEBRA, if a -> b HOLDS and b -> C holds then a -> c also hold. a -> b is called as a functionally determines b.

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