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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

1.

An n-array relationship is drawn using which symbol:(a) A diamond(b) A line with arrows showing direction(c) A line without arrows showing direction(d) A rectangleI had been asked this question in a national level competition.I need to ask this question from Attribute, Tuple and Entity topic in division Planning Oracle Applications of Oracle

Answer»

The correct option is (a) A diamond

Explanation: When a single PARENT-child RELATIONSHIP exists, the relationship is called binary. All of the previous examples of relationships to this point have been binary relationships. However, when creating a DATA model, it is not uncommon to come across n-array relationships, the MODELING name for relationships between two or more parent entities and a single child table.

2.

The relational model is based on the concept that data is organized and stored in two-dimensional tables called _____________(a) Fields(b) Records(c) Relations(d) KeysThe question was asked during an internship interview.Origin of the question is Attribute, Tuple and Entity topic in portion Planning Oracle Applications of Oracle

Answer»

The correct answer is (b) Records

Easy explanation: In the context of a RELATIONAL database, a row also CALLED a record or tuple represents a single, IMPLICITLY STRUCTURED data item in a table.

3.

A ___________ normal form normalization will be needed where all attributes in a relation tuple are not functionally dependent only on the key attribute.(a) First(b) Second(c) Third(d) FourthI have been asked this question by my school principal while I was bunking the class.This intriguing question originated from Attribute, Tuple and Entity in division Planning Oracle Applications of Oracle

Answer» RIGHT OPTION is (c) Third

The EXPLANATION is: A database is in third normal form if it satisfies the FOLLOWING conditions:1)It is in second normal form. 2)There is no transitive functional dependency
4.

An aggregation association is drawn using which symbol:(a) a line which loops back onto the same table(b) small closed diamond at the end of a line connecting two tables(c) small open diamond at the end of a line connecting two tables(d) small triangle at the end of a line connecting the aggregated item and multiple component itemsThe question was posed to me during an online exam.I would like to ask this question from Attribute, Tuple and Entity in portion Planning Oracle Applications of Oracle

Answer»

Right option is (c) small open diamond at the end of a line connecting two tables

Easy explanation: There are THREE primary inter-object relationships: ASSOCIATION, aggregation, and composition. Using the right relationship line is important for placing implicit restrictions on the visibility and propagation of changes to the related classes, matter which PLAY major role in REDUCING system complexity.

5.

Identify the criteria for designing database from the point of view of user(a) No redundancy(b) No inapplicable attributes(c) Uniformity in naming & definitions of the data items(d) All of the MentionedI had been asked this question during an internship interview.My question comes from Attribute, Tuple and Entity in division Planning Oracle Applications of Oracle

Answer»

Right answer is (d) All of the Mentioned

The best explanation: To DESIGNING database from the POINT of USER view we need all the mentioned REQUIRED.

6.

Which of the following is record based logical model?(a) Network Model(b) Object oriented model(c) E-R Model(d) None of the MentionedThe question was asked during an interview.My enquiry is from Attribute, Tuple and Entity topic in portion Planning Oracle Applications of Oracle

Answer»

The CORRECT answer is (a) Network MODEL

Explanation: The network model is a database model conceived as a FLEXIBLE WAY of representing objects and their relationships.

7.

E-R model uses this symbol to represent weak entity set ?(a) Dotted rectangle(b) Diamond(c) Doubly outlined rectangle(d) None of the MentionedThe question was posed to me in examination.My question is from Attribute, Tuple and Entity in division Planning Oracle Applications of Oracle

Answer»

The CORRECT OPTION is (c) DOUBLY outlined rectangle

Explanation: A weak ENTITY set is indicated by a doubly-outlined BOX.

8.

A relational database developer refers to a record as(a) A criteria(b) A relation(c) A tuple(d) An attributeI had been asked this question in a national level competition.I want to ask this question from Attribute, Tuple and Entity in portion Planning Oracle Applications of Oracle

Answer»

The CORRECT OPTION is (C) A tuple

Explanation: A tuple is analogous to a record in non-relational databases.

9.

The relational model feature is that there(a) is no need for primary key data(b) is much more data independence than some other database models(c) are explicit relationships among records(d) are tables with many dimensionsThe question was asked during an interview for a job.My question is based upon Attribute, Tuple and Entity topic in division Planning Oracle Applications of Oracle

Answer» RIGHT answer is (b) is much more data INDEPENDENCE than some other database models

The explanation is: The relational MODEL is the CONCEPTUAL basis of relational databases. Proposed by E.F.Codd in 1969, it is a method of structuring data using relations, which are grid-like mathematical structures consisting of columns and rows.
10.

In an E-R diagram an entity set is represent by a(a) Rectangle(b) Ellipse(c) Diamond box(d) CircleI got this question during an interview.My doubt is from Attribute, Tuple and Entity topic in portion Planning Oracle Applications of Oracle

Answer»

The CORRECT answer is (a) Rectangle

Easy EXPLANATION: Entity types REPRESENT sets of objects and are pictured by RECTANGULAR NODES.

11.

In a database, a foreign key is ?(a) A data element/attribute within a data field of a data record that is not unique, and cannot be used to distinguish one data record in a database from another data record within a database table(b) A data element/attribute within a data field of a data record within a database table that is a secondary key in another database table(c) A data element/attribute within a data field of a data record within a database table that is a primary key in another database table(d) A data element/attribute within a data field of a data record that enables a database to uniquely distinguish one data record in a database from another data record within a database tableThe question was posed to me at a job interview.I'm obligated to ask this question of Foreign, Candidate, Primary, Composite, Unique Keys topic in chapter Planning Oracle Applications of Oracle

Answer»

The correct choice is (c) A data element/attribute within a data FIELD of a data record within a database table that is a PRIMARY key in another database table

The BEST I can explain: A FOREIGN KEY CONSTRAINT can reference columns in tables in the same database or within the same table. These are called self-referencing tables. For example, consider an employee table that contains three columns: employee_number, employee_name, and manager_employee_number. Because the manager is also an employee, there is a foreign key RELATIONSHIP from the manager_employee_number column to the employee_number column.

12.

A Foreign key is combined with a foreign key creates(a) Parent child relationship between the tables that connect them(b) Many-Many relationship between the tables that connect them(c) Network model between the tables that connect them(d) None of the MentionedThe question was posed to me in semester exam.The doubt is from Foreign, Candidate, Primary, Composite, Unique Keys topic in division Planning Oracle Applications of Oracle

Answer»

Correct answer is (a) Parent child relationship between the tables that connect them

To explain I would SAY: In a FOREIGN key reference, a link is created between two tables when the column or columns that hold the primary key VALUE for one table are referenced by the column or columns in ANOTHER table. This column becomes a foreign key in the second table.

13.

Which of the following statements is not correct?(a) The primary key must be unique for a given table(b) Specifying a zero (0) for the lower bound for the association multiplicity on a class diagram indicates that the item is required(c) Specifying a one (1) for the lower bound for the association multiplicity on a class diagram indicates that the item is required(d) Most databases allow multiple records that are identicalI got this question during a job interview.This key question is from Foreign, Candidate, Primary, Composite, Unique Keys topic in portion Planning Oracle Applications of Oracle

Answer»

Correct choice is (b) Specifying a zero (0) for the LOWER bound for the association multiplicity on a class diagram INDICATES that the item is required

Easy EXPLANATION: A foreign key is a column that references a column (most often the primary key) of another table. The purpose of the foreign key is to ensure referential integrity of the data. In other WORDS, only values that are supposed to appear in the database are permitted.

14.

A Key which is a set of one or more columns that can identify a record uniquely is called?(a) Natural key(b) Candidate key(c) Not Null key(d) Alternate keyThe question was asked in an interview for internship.I'm obligated to ask this question of Foreign, Candidate, Primary, Composite, Unique Keys topic in portion Planning Oracle Applications of Oracle

Answer»

Correct answer is (b) Candidate key

For explanation: A candidate key is a combination of attributes that can be uniquely used to IDENTIFY a database RECORD without any extraneous data. Each table may have one or more candidate KEYS. One of these candidate keys is selected as the table PRIMARY key.

15.

Which key accepts multiple NULL values?(a) Foreign Key(b) Unique Key(c) Primary Key(d) None of the MentionedI got this question in an interview for job.I want to ask this question from Foreign, Candidate, Primary, Composite, Unique Keys in section Planning Oracle Applications of Oracle

Answer»

Correct choice is (a) FOREIGN Key

Easy EXPLANATION: A foreign key is a key USED to link two TABLES together. This is sometimes called a REFERENCING key.Foreign Key is a column or a combination of columns whose values match a Primary Key in a different table.

16.

By default, which key creates Clustered index?(a) Foreign Key(b) Unique Key(c) Primary Key(d) None of the MentionedI have been asked this question in an interview.My question comes from Foreign, Candidate, Primary, Composite, Unique Keys topic in portion Planning Oracle Applications of Oracle

Answer»

The CORRECT ANSWER is (C) Primary Key

Best explanation: Primary Key by default it ADDS a clustered index.

17.

What is true about Unique and primary key?(a) Unique can have multiple NULL values but Primary can’t have.(b) Unique can have single NULL value but Primary can’t have even single.(c) Both can have duplicate values(d) None of the MentionedThe question was posed to me in homework.My doubt stems from Foreign, Candidate, Primary, Composite, Unique Keys topic in section Planning Oracle Applications of Oracle

Answer»

Right OPTION is (b) UNIQUE can have single NULL value but Primary can’t have even single.

To EXPLAIN I would SAY: Primary key doesn’t allow Null values and Unique key allows Null value, but only ONE Null value.

18.

Which of the following is not a Key in SQL Server?(a) Primary(b) Foreign(c) Alternate(d) SecondaryThis question was addressed to me in a job interview.My question is taken from Foreign, Candidate, Primary, Composite, Unique Keys topic in section Planning Oracle Applications of Oracle

Answer»

Right option is (d) Secondary

The best I can explain: Except Secondary all are the TYPES of KEY in SQL SERVER.

19.

A _______________ key is a minimal super key(a) Primary(b) Foreign(c) Candidate(d) Non-PrimeI had been asked this question in quiz.My question is based upon Foreign, Candidate, Primary, Composite, Unique Keys topic in section Planning Oracle Applications of Oracle

Answer»

Right CHOICE is (C) CANDIDATE

The explanation: In the relational model of databases, a candidate key of a relation is a MINIMAL SUPERKEY for that relation.

20.

How can a SQL developer add a key on a table?(a) While creating a table(b) With Alter table command(c) With SQL server Properties window(d) All of the MentionedI have been asked this question by my college professor while I was bunking the class.My question comes from Foreign, Candidate, Primary, Composite, Unique Keys in division Planning Oracle Applications of Oracle

Answer»

Right answer is (d) All of the MENTIONED

Easiest EXPLANATION: Adding KEY on a table can be DONE with all the above mentioned way.

21.

Which of the following is not a restriction for a table to be a relation?(a) The cells of the table must contain a single value(b) All of the entries in any column must be of the same kind(c) The columns must be ordered(d) No two rows in a table may be identicalI got this question during an interview.The query is from Normalization topic in chapter Planning Oracle Applications of Oracle

Answer» RIGHT answer is (C) The columns must be ordered

The EXPLANATION: To FORMAT the columns differently, assign a UNIQUE alias to each column within the SELECT command itself (do not use the ALIAS clause of the COLUMN command) and enter a COLUMN command for each column’s alias.
22.

When the values in one or more attributes being used as a foreign key must exist in another set of one or more attributes in another table, we have created a(n):(a) Transitive Dependency(b) Insertion Anomaly(c) Referential Integrity Constraint(d) Normal FormI had been asked this question during an interview.This intriguing question comes from Normalization in portion Planning Oracle Applications of Oracle

Answer»

Right answer is (c) Referential INTEGRITY Constraint

For EXPLANATION I WOULD SAY: Referential Integrity is set of constraints applied to foreign key which prevents ENTERING a row in child table for which you don’t have any corresponding row in parent table i.e. entering NULL or invalid foreign keys.

23.

Every time attribute A appears, it is matched with the same value of attribute B, but not the same value of attribute C. Therefore, it is true that:(a) A -> B(b) A -> C(c) A -> (B,C)(d) (B,C) -> AI have been asked this question by my college director while I was bunking the class.Asked question is from Normalization in chapter Planning Oracle Applications of Oracle

Answer»

The correct choice is (a) A -> B

To explain I WOULD say: TRANSITIVITY rule: Same as transitive rule in ALGEBRA, if a -> b HOLDS and b -> C holds then a -> c also hold. a -> b is called as a functionally determines b.

24.

In a given relationship R, if an attribute A uniquely defines all other attributes, then the attribute A is a key attribute which is also known as the _________ key.(a) Candidate(b) Join(c) Functional(d) None of the MentionedI have been asked this question in examination.This is a very interesting question from Normalization in division Planning Oracle Applications of Oracle

Answer»

The correct answer is (a) Candidate

The explanation is: A candidate key is a column, or SET of columns, in a table that can uniquely identify any DATABASE record without referring to any other data. Each table MAY have ONE or more candidate KEYS.

25.

Anomalies are avoided by splitting the offending relation into multiple relations, is also known as(a) Accupressure(b) Decomposition(c) Precomposition(d) Both Decomposition and PrecompositionI had been asked this question in quiz.My doubt is from Normalization topic in section Planning Oracle Applications of Oracle

Answer»

Right option is (B) Decomposition

To elaborate: ELIMINATE REDUNDANCY by decomposing a relation into several relations in a HIGHER normal form.

26.

A ___________ is an indirect functional dependency, one in which X->Z only by virtue of X->Y and Y->Z.(a) Multivalued Dependencies(b) Join Dependency(c) Trivial Functional Dependency(d) Transitive DependenciesI had been asked this question in examination.The query is from Normalization topic in section Planning Oracle Applications of Oracle

Answer»

The correct choice is (d) Transitive DEPENDENCIES

To explain I would say: Third Normal Form DEALS with something called ‘transitive’ dependencies. This MEANS if we have a primary key A and a non-key domain B and C where C is more dependent on B than A and B is directly dependent on A, then C can be considered transitively dependent on A.

27.

Every constraint on the table is a logical consequence of the table’s(a) Fourth normal form(b) Fifth normal form(c) Domain/key normal form(d) None of the MentionedThis question was addressed to me in an online quiz.The origin of the question is Normalization in chapter Planning Oracle Applications of Oracle

Answer»

Correct CHOICE is (c) Domain/key normal form

The EXPLANATION is: A relation is in domain-key normal form (DK/NF) if every CONSTRAINT on the relation is a LOGICAL CONSEQUENCE of the definition of keys and domains.

28.

A table is in 3NF if it is in 2NF and if it has no ____________(a) Functional Dependencies(b) Transitive Dependencies(c) Trivial Functional Dependency(d) Multivalued DependenciesThe question was asked in an online quiz.This intriguing question originated from Normalization in section Planning Oracle Applications of Oracle

Answer»

Correct option is (B) Transitive Dependencies

Easy explanation: For a relation to be in Third Normal Form, it MUST be in Second Normal form and the following must SATISFY:No non-prime attribute is TRANSITIVELY dependent on prime key attribute For any non-trivial functional DEPENDENCY, X -> A, then eitherX is a superkey or,A is prime attribute.

29.

A table is in BCNF if it is in 3NF and if every determinant is a ___________ key.(a) Dependent(b) Normal(c) Candidate(d) Both Normal and CandidateThis question was addressed to me in an interview for internship.This interesting question is from Normalization in chapter Planning Oracle Applications of Oracle

Answer» RIGHT ANSWER is (c) Candidate

The explanation: A table is in Boyce-Codd normal FORM (BCNF) if and only if it is in 3NF and every determinant is a candidate KEY.
30.

The ___________ normalization introduced by Chris Date, Hugh Darwen, and Nikos Lorentzos.(a) Third(b) Fourth(c) Fifth(d) SixthI had been asked this question by my school teacher while I was bunking the class.My question is based upon Normalization in section Planning Oracle Applications of Oracle

Answer» CORRECT answer is (d) Sixth

The EXPLANATION: Chris Date, Hugh DARWEN, and Nikos Lorentzos introduced Sixth Normal form (6NF).
31.

The benefits of a standard relational language include which of the following ?(a) Reduced training costs(b) Increased dependence on a single vendor(c) Applications are not needed(d) All of the MentionedThis question was posed to me in unit test.My doubt stems from Data Entry, Query and Reporting topic in division Planning Oracle Applications of Oracle

Answer»

Correct choice is (a) REDUCED training COSTS

Easiest explanation: Standard RELATIONAL language GIVES the benefits of reducing the training costs.

32.

Each answer below shows example data from a table. Which answer is an example of the general-purpose remarks column problem?(a) Three columns have the values 534-2435, 534-7867, and 546-2356 in the same row(b) Three rows have the values Brown Small Chair, Small Chair Brown, and Small Brown Chair in the same column(c) Three rows have the values Brown, NULL, and Blue in the same column(d) One row has the value “He is interested in a Silver Porsche from the years 1978-1988” in a columnI have been asked this question in an online interview.This is a very interesting question from Data Entry, Query and Reporting in portion Planning Oracle Applications of Oracle

Answer»

Correct answer is (d) ONE row has the value “He is interested in a SILVER Porsche from the years 1978-1988” in a COLUMN

The best EXPLANATION: Option d fullfill the condition of column.

33.

The wildcard in a WHERE clause is useful when?(a) An exact match is necessary in a SELECT statement(b) An exact match is not possible in a SELECT statement(c) An exact match is necessary in a CREATE statement(d) An exact match is not possible in a CREATE statementThis question was posed to me by my school teacher while I was bunking the class.My enquiry is from Data Entry, Query and Reporting topic in chapter Planning Oracle Applications of Oracle

Answer»

Correct CHOICE is (B) An exact match is not possible in a SELECT STATEMENT

Easy explanation: Wildcard USEFUL only when an exact match is not possible in a SELECT statement.

34.

Which of the following is not a component of a data warehouse?(a) Data extraction/cleaning/preparation programs(b) Data warehouse data(c) Data metadata(d) None of the MentionedThis question was posed to me in quiz.This question is from Data Entry, Query and Reporting topic in division Planning Oracle Applications of Oracle

Answer» CORRECT choice is (c) Data METADATA

For explanation: Data warehouse is not DEAL with the Data metadata.
35.

A report generated by a reporting system is delivered to the appropriate users via a user-accessed Web site. This system uses which of the following report modes?(a) Push(b) Pull(c) RFM(d) OLAPI got this question in an internship interview.This interesting question is from Data Entry, Query and Reporting in chapter Planning Oracle Applications of Oracle

Answer»

Correct choice is (B) Pull

For EXPLANATION: The push-pull MODEL to not allow mixed port type combinations for a connection, such as connecting a push OUTPUT port to a pull INPUT port, and a pull output port to a push input port.

36.

The “curse of dimensionality” relates to which problem of using operational data for BI reporting?(a) Dirty data(b) Inconsistent data(c) Too much data(d) Non-integrated dataI have been asked this question in class test.My question is taken from Data Entry, Query and Reporting topic in portion Planning Oracle Applications of Oracle

Answer»

Right option is (c) Too much data

For EXPLANATION: The curse of dimensionality refers to various phenomena that ARISE when ANALYZING and organizing data in high-dimensional spaces.

37.

Business Intelligence (BI) reporting systems cannot do which of the following operations?(a) Filter data(b) Group data(c) Modify data(d) Both filter and group dataI had been asked this question during an interview.I'm obligated to ask this question of Data Entry, Query and Reporting in chapter Planning Oracle Applications of Oracle

Answer»

Correct choice is (c) Modify data

Easy explanation: BUSINESS intelligence (BI) is a technology-driven PROCESS for filter data and group information.

38.

A BI reporting system does not _____________(a) Create meaningful information(b) Deliver information to users on a timely basis(c) Use statistical procedures to predict future events(d) Use disparate data sourcesThe question was posed to me in a job interview.My question is from Data Entry, Query and Reporting in chapter Planning Oracle Applications of Oracle

Answer»

The correct choice is (c) USE statistical PROCEDURES to predict future events

Explanation: Business intelligence (BI) is a technology-driven process for analyzing data and PRESENTING ACTIONABLE INFORMATION.

39.

Which of the following is not one of the three ways to classify an action assertion?(a) Condition(b) Integrity Control(c) Authorization(d) EnablerThe question was posed to me in unit test.My question comes from The Atomic Data Models and Business Models topic in division Planning Oracle Applications of Oracle

Answer»

Right choice is (d) Enabler

The EXPLANATION is: The CREATE ASSERTION statement names a NEW CONSTRAINT and defines the Constraint’s deferral mode, initial constraint CHECK time and its CHECK search condition.

40.

Use of a supertype/subtype relationship is necessary when which of the following exists?(a) An instance of a subtype participates in a relationship that is unique to that subtype(b) An instance of a subtype participates in a relationship that is the same as the other subtypes(c) Attributes apply to all of the instances of an entity type(d) No attributes apply to any of the instances of an entity typeI got this question in my homework.My doubt is from The Atomic Data Models and Business Models topic in division Planning Oracle Applications of Oracle

Answer»

Right answer is (a) An INSTANCE of a SUBTYPE participates in a relationship that is unique to that subtype

The explanation: Super-types and sub-types show HIERARCHY in the structure; graphs and TREES show hierarchy in the data.

41.

Which of the following statements concerning business rules is true?(a) It should be complex(b) It should not be convertible to computer code(c) It may include restrictions(d) All of the MentionedThe question was posed to me in semester exam.This is a very interesting question from The Atomic Data Models and Business Models in section Planning Oracle Applications of Oracle

Answer» RIGHT answer is (c) It may include restrictions

For explanation I WOULD say: It is used to DEFINE, deploy, execute, monitor and maintain the variety and complexity of decision logic that is used by operational systems within an ORGANIZATION or ENTERPRISE.
42.

A supertype/subtype hierarchy is which of the following?(a) Each subtype has only one attribute(b) Each supertype has only one attribute(c) Each subtype has only one supertype(d) Each supertype has only one subtypeThis question was posed to me in a national level competition.This intriguing question comes from The Atomic Data Models and Business Models topic in section Planning Oracle Applications of Oracle

Answer»

Right ANSWER is (c) Each subtype has only one supertype

Easy explanation: Two ENTITIES are of DISTINCT types if they have no attributes in common. It is POSSIBLE for entities to have both common and distinct attributes. If they have a common identifier (that is, a common primary KEY), they have a special supertype-subtype relationship: they are neither distinct nor the same.

43.

When an entity instance must be a member of only one sub-type, it is which of the following?(a) Disjoint with total specialization(b) Disjoint with partial specialization(c) Overlap with total specialization(d) Overlap with partial specializationThis question was addressed to me during an online interview.This intriguing question originated from The Atomic Data Models and Business Models in section Planning Oracle Applications of Oracle

Answer»

The correct option is (a) Disjoint with TOTAL specialization

The explanation is: GradStudent (_id_, NAME, gradStuff) UndergradStudent (_id_, name, underGradStuff) Professor (_id_, name) TEACHES(_prof_id_, _stud_id_)

Considering that the relational database above is meant to represent total disjoint specialization, i.e. there is no table Student but rather two completely separate ones, when writing this in SQL in ORDER to implement the database, how would I fetch the student id for the Teaches table? I cannot figure out how to MAKE a foreign key from two different tables.

44.

Which of the following is the process of selecting the data storage and data access characteristics of the database?(a) Logical database design(b) Physical database design(c) Testing and performance tuning(d) Evaluation and selectingI had been asked this question by my school principal while I was bunking the class.I'd like to ask this question from The Atomic Data Models and Business Models topic in section Planning Oracle Applications of Oracle

Answer»

Right OPTION is (b) Physical DATABASE design

Easiest explanation: Physical database design is the PROCESS of SELECTING the data storage and data access characteristics of the database.

45.

If the state of the database no longer reflects a real state of the world that the database is supposed to capture, then such a state is called(a) Consistent state(b) Inconsistent state(c) Durable state(d) Atomic stateThis question was addressed to me in an internship interview.The doubt is from The Atomic Data Models and Business Models in chapter Planning Oracle Applications of Oracle

Answer»

Correct CHOICE is (b) Inconsistent state

The best explanation: If the state of the database no LONGER REFLECTS a real state of the world that the database is SUPPOSED to capture, then such a state is calledin CONSISTENT state.

46.

The relationship between DEPARTMENT and EMPLOYEE is a(a) One-to-one relationship(b) One-to-many relationship(c) Many-to-many relationship(d) Many-to-one relationshipThe question was posed to me during a job interview.My question is from The Atomic Data Models and Business Models in division Planning Oracle Applications of Oracle

Answer» RIGHT choice is (B) One-to-many RELATIONSHIP

For explanation: The relationship between DEPARTMENT and EMPLOYEE is aone-to-many relationship.
47.

A collection of data designed to be used by different people is called a/an(a) Organization(b) Database(c) Relationship(d) SchemaThis question was addressed to me in exam.The origin of the question is The Atomic Data Models and Business Models topic in portion Planning Oracle Applications of Oracle

Answer» RIGHT answer is (B) Database

For EXPLANATION: A collection of data designed to be USED by different people is called a data base.
48.

Which of the following is the oldest database model?(a) Relational(b) Deductive(c) Physical(d) NetworkI got this question in semester exam.My question is taken from The Atomic Data Models and Business Models topic in division Planning Oracle Applications of Oracle

Answer» CORRECT OPTION is (d) NETWORK

Easiest explanation: Network Model is the OLDEST database model.
49.

In order to use a record management system(a) you need to understand the low level details of how information is stored(b) you need to understand the model the record management system uses(c) you need to understandboth information storage and the model of record management system(d) None of the MentionedThe question was asked in an online quiz.This question is from Planning Oracle Applications in section Planning Oracle Applications of Oracle

Answer»

The correct ANSWER is (b) you need to UNDERSTAND the model the RECORD management system uses

The best EXPLANATION: For get to know the RMS (Record Management System) you should know the FLOW and of model and record management system.

50.

Which of the following statements concerning business rules is true?(a) It should be complex.(b) It should not be convertible to computer code.(c) It may include restrictions.(d) All of the MentionedThis question was addressed to me during an online exam.The query is from Planning Oracle Applications topic in portion Planning Oracle Applications of Oracle

Answer»

The correct CHOICE is (c) It may include restrictions.

For explanation I WOULD say: According to the business rule it ALWAYS may include restrictions.