1.

Ex. 2. A body weighs 500 gf in air and 450 gf when wholly immersed in water. Calculate : (i) the loss in weight of the body in water.(ii) the upthrust of the body.(iii) volume of the body​

Answer»

Weight of BODY in AIR,W=450gf=450g dynesWeight of body in water,W =310gf=310g dynesLet d be the density of the body,v be the volume .Let q be the density of water.Now,W=Vdg-->450 g =VdgBuoyant force , B =Vgq-->B= Vg[q=1g/cm3]Now, W/=W-B-->310g = 450g-Vg-->v =140 cm3Loss in weight =BUOYANT force = Vqg=140×1×g=140g dynes=140gfAgain upthrust =Buoyant force = 140 gfHope it helps...



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