InterviewSolution
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InterviewSolution
| 1. |
Example 1.6 A car accelerates uniformly from 18 km h-1 to 36 km h-1 in S(i) the acceleration and (ii) the distance covered by the car in that time. |
| Answer» <p>Acceleration = Change in Velocity/Time Change in Velocity = 36-18 = 18 km/h=5 m/s Time= 5 Seconds Acceleration = 5/5= 1 m/s2 </p><p>Equation of motion,s=ut+(1/2)at2 u=18 km/h=5 m/s t=5 s a=1 m/s2 s= (5*5)+(1/2*1*5*5) s=25+12.5 i.e., s=37.5 m </p> <p>hit like if you find it useful</p> | |