Example 1.6 A car accelerates uniformly from 18 km h-1 to 36 km h-1 in

1.	Example 1.6 A car accelerates uniformly from 18 km h-1 to 36 km h-1 in S(i) the acceleration and (ii) the distance covered by the car in that time.
Answer» Acceleration = Change in Velocity/Time Change in Velocity = 36-18 = 18 km/h=5 m/s Time= 5 Seconds Acceleration = 5/5= 1 m/s2 Equation of motion,s=ut+(1/2)at2 u=18 km/h=5 m/s t=5 s a=1 m/s2 s= (55)+(1/2155) s=25+12.5 i.e., s=37.5 m hit like if you find it useful

Example 1.6 A car accelerates uniformly from 18 km h-1 to 36 km h-1 in S(i) the acceleration and (ii) the distance covered by the car in that time.

Answer»

Acceleration = Change in Velocity/Time Change in Velocity = 36-18 = 18 km/h=5 m/s Time= 5 Seconds Acceleration = 5/5= 1 m/s2

Equation of motion,s=ut+(1/2)at2 u=18 km/h=5 m/s t=5 s a=1 m/s2 s= (5*5)+(1/2*1*5*5) s=25+12.5 i.e., s=37.5 m

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