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Example 3. Prove that 4 sin 30° sin^2 60°+3 cos 60° tan 45º = 2 sec^2 60° - cosec^ 2 90° |
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Answer» -STEP EXPLANATION:LHS 4 sin30° sin²60° +3 cos60°tan45°= 4× ½ × ¾ + 3 ×½ × 1=3/2 + 3/2= 6/2=3RHS2sec60° - cosec² 90°= 2 ×2 - 1²= 4 -1=3 LHS = RHS Small CORRECTION in the question -> In RHS it is 2sec60° ,but not 2 sec²60° |
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