Example 41. Calculate the number of atoms of oxygenresent in 88 g of C – InterviewSolution

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1.	Example 41. Calculate the number of atoms of oxygenresent in 88 g of CO2. What would be the weight of COaving same number of oxygen atoms?
Answer» <p>Molecular weight of CO2 =44 and it has 32g O2 and one molecule of O2 has 2 atoms.44gCO2 has 2N atoms of O88g CO2 has 2N atoms =(2×6.023×1023×88)/44⇒24.092×1023atoms of O2CO=28N atoms of O present in 28g CO24.092×1023 atoms of O=(28×24.092×1023)/6.023×1023⇒112g CO</p>

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