Example 7: A girl of height 90 cm is walking away from the base of alamp-post at a speed of 1.2 m/s. If the lampis 3.6 m above the ground, find the lengthof her shadow after 4 seconds.

Example 7: A girl of height 90 cm is walking away from the base of a

1.	Example 7: A girl of height 90 cm is walking away from the base of alamp-post at a speed of 1.2 m/s. If the lampis 3.6 m above the ground, find the lengthof her shadow after 4 seconds.
Answer» Let the girl be at point D on the GROUND from the lamppost after 4 sec. ∴ BD = 1.2 m/sec × 4 sec = 4.8 m = 480 CM Suppose the length of the shadow of the girl be x cm when she at POSITION D. ∴ ED = x cm In ∆EDC and ∆EBA ∠EDC = ∠EBA (90°) ∠DEC = ∠BEA (Common) ∴ ∆EDC ∼ ∆EBA (AA SIMILARITY) EC/EA = DC/BA = ED/BE EC/EA = ED/BE 90cm/360cm = x cm/(480+x) cm 1/4 = x/x+480 4x = x + 480 3x = 480 x = 480/3 x = 160 (corresponding sides or proportional) ∴ Length of her shadow after 4 second is 160 cmStep-by-step explanation:

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Example 7: A girl of height 90 cm is walking away from the base of alamp-post at a speed of 1.2 m/s. If the lampis 3.6 m above the ground, find the lengthof her shadow after 4 seconds.​

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Example 7: A girl of height 90 cm is walking away from the base of alamp-post at a speed of 1.2 m/s. If the lampis 3.6 m above the ground, find the lengthof her shadow after 4 seconds.