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Example 9.1 A constant force aOnobject of mass b kg for a duratio2 s. It increases the object's vefrom 3 m s1 to 7 m simagnitude of the applied force. Nowthe force was applied for a duration5 s, what would be the final velocitythe object?Find t

Answer»

Let the force be F,Mass is M,time for which it is accelerated = 2svelocity is increased from 3m/s to 7m/sso, acceleration is , a = (7-3)/2 = 2m/s²The force applied is, F = ma = (5)(2) = 10 NNow, the force is applied for 5s, the velocity after 5s will be,v=u+at=> v =3+(2)(5)=>v=13m/s , this is final velocity.



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