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Excess of AgCl is added to 0.1 M solution of KBr at 298 K. Calculate the equilibrium concentrations of Br^(-) and Cl^(-) ions. E_(Cl^(-)//AgCl//Ag)^(@)=0.222" volt"E_(Br^(-)//AgBr//Ag)^(@)=0.095 volt

Answer»


Solution :`{:(,AgCl,+,Br^(-),hArr,AGBR,+,Cl^(-)),("At equilibrium,",,,(0.1-X),,,,x):}`
APPLY `log K =E_(cell)^(@)/0.0591`
or `"log"x/((0.1-x))=E_(cell)^(@)/0.0591`


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