1.

Excess of conc. H_(2)SO_(4) reacts with C_(2)H_(2)OH at 413 K to form.

Answer»

`C_(2)H_(5)HSO_(4)`
`(C_(2)H_(5))_(2)SO_(4)`
`CH_(2)=CH_(2)`
`C_(2)H_(6)OC_(2)H_(5)`

Solution :Alcohol is dehydrated to give alkene. It is a `BETA-"elimination"`
`CH_(3)-CH_(2)-OH underset(-H_(2)O)overset(H_(2)SO_(4).443K)to CH_(2)=CH_(2)`
Note: At 413K, ethyl ether is obtained
`C_(2_)H_(5)OH +HCO_(2)H_(5) underset(-H_(2)O) overset(H_(2)SO_(4).443K)to C_(2)H_(5)OC_(2)H_(5)`


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