1.

Excess of silver nitrate solution is added to 100 ml of 0.01 M pentaaqua chloro chromium (III) chloride solution .The mass of silver chloride obtained in grams is [Atomic mass of silver is 108]

Answer»

`287xx10^(-3)`
`143.5xx10^(-3)`
`143.5xx10^(2)`
`287xx10^(-2)`

Solution :`[Cr(H_(2)O_(5))_(5)Cl]Cl_(2)underset(AgNO_(3))overset(Excess)to`
`[Cr(H_(2)O)_(5)Cl]^(+)NO_(3)^(-)+2AgCldarr`
Thus Meq. Of `Cl^(-)` ions outside=Meq. Of AGCL FORMED
`THEREFORE` NUMBER of moles of `Cl^(-)` ions present
`=(2xx100xx0.01)/(1000)=0.002 `moles
`therefore` Mass of AgCl=`0.002xx143.5`
=0.287 g=`287xx10^(-3)g`


Discussion

No Comment Found

Related InterviewSolutions