1.

Excited state configuration of Mn^(2+) is

Answer»

`t_(2G)^(4)`
`t_(2g)^(3)c_(g)^(2)`
`t_(2g)^(4)c_(g)^(2)`
`t_(2g)^(5)c_(g)^(0)`

Solution :After crystal field spliting, the five d-orbitals. Get separated as THREE `t_(2g)` and two orbitals. For `Mn^(2+)`, last shell has `5e^(-)`s i.e., `3D^(5).4s^(0)`. So according to Hund's rule of maximum multiplicity the excited STATE configuration will be `t_(2g)^(3)e_(g)^(2)`.


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