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InterviewSolution
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EXERCISE 3.1Fig. 3.13, lines AB and CD intersect at O. IfA0C < BOE = 70° and BOD-40", findOE and reflex Z COEFig, 3.13 |
| Answer» <p>∠AOC + ∠BOE = 70°</p><p>∠AOC + ∠COE + ∠BOE = 180°[ linear pair ]</p><p>So, if ∠AOC + ∠BOE = 70°so,→ 70° + ∠COE = 180°</p><p>→ ∠COE = 180 - 70</p><p>→ ∠COE = 110°</p><p>.</p><p>∠BOD = ∠AOC [ Vertically Opposite Angles ]</p><p>.</p><p>Now,→ ∠AOC + ∠COE + ∠BOE = 180°</p><p>→ 40° + 110° + ∠BOE = 180°</p><p>→ 150° + ∠BOE = 180°</p><p>→ ∠BOE = 180° - 150°</p><p>→ ∠BOE = 30°</p><p>.</p><p>∠BOD + ∠DOA = 180° [Liner Pair]</p><p>→ 40° + ∠DOA = 180°</p><p>→ ∠DOA = 180° - 40°</p><p>→ ∠DOA = 140°</p><p>Hence,reflex angle ( ∠COE ) = ∠AOC + ∠DOE + ∠BOD + ∠BOE</p><p>reflex angle ( ∠COE ) = 40° + 140° + 40° + 30°</p><p>reflex angle ( ∠COE ) = 250°</p><p>Like my answer if you find it useful!</p> | |