1.

Expand - 1sum (2x + 3y - 4z)² 2sum (x + 3y)³​

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Answer:

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(2x+3Y+4z)

2

=(2x)

2

+(3y)

2

+(4z)

2

+(2×2x×3y)+(2×3y×4z)+(2×4z×2x)

(∵(a+b+C)

2

=a

2

+b

2

+c

2

+2ab+2bc+2ca)

=4x

2

+9y

2

+16z

2

+12xy+24yz+16zx

Hence, (2x+3y+4z)

2

=4x

2

+9y

2

+16z

2

+12xy+24yz+16zx.

4x

2

+9y

2

+16z

2

+12xy+24yz+16zx

Step-by-step EXPLANATION:

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