InterviewSolution
Saved Bookmarks
| 1. |
Expand `(2a+3b+4c)^2`. |
|
Answer» Putting `2a-x,3b=y and 4c=z`, we get `(2a+3b+4c)^2` `=(x+y+z)^2` `=x^2+y^2+z^2+2xy+2yz+2zx` ` =(2a)^2+(3b)^2+(4c)^2+{2xx (2a) xx (3b)}+{2xx(3b)xx(4c)}+{2xx (4c)xx (2a)}` `=4a62+9b^2+16c^2+12ab+24bc+2zx`. |
|