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If `a+b+c=0` then `((a^2)/(bc)+(b^2)/(ca)+(c^2)/(ab))=?`A. 1B. 0C. -1D. 3

Answer» Correct Answer - D
`a+b+c=0 rArr a^3+b^3+c^3-3abc=0rArr a^3+b^3+c^3=3abc`.
Now , `((a^2)/(bc)+(b^2)/(ca)+(c^2)/(ab))=(a^3+b^3+c^3)/(abc)=(3abc)/(abc)=3`.


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