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Expand the log ax×by/cz |
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Answer» ain rule will be applied…Consider (2x+1) = ANOW differentiate on both sides with RESPECT to ‘a’, we get,2dx/da = 1So, dx/da = 1/2 …(Eqn. 1)Now, PUT (2x+1)=a in the main equation, you’ll GETY= a^5Differentiating on both sides with respect to ‘a’ we get,dy/da= 5a^4 …(Eqn. 2)Now divide (Eqn. 2) by (Eqn. 1), we get(dy/da)/(dx/da) =5a^4/(1/2)So, dy/dx= 10a^4Resubstituting value of ‘a’, we getdy/dx= 10(2x+1)^4 |
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