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Experiment shows that Nickel oxide has the formula Ni_(0.96)O_(1.00). What friction of Nickel exists as of Ni^(2+) and Ni^(3+) ions ? |
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Answer» Solution :`"Let the NUMBER of "Ni^(2+)" ion "=x` Then the number of Square CLOSE packing : When the spheres of the second row are placed EXACTLY above those of the first row. This way the spheres are aligned horizontally as well as VERTICALLY. The arrangement is AAA type. Coordination number is 4. `Ni^(3+)" ion will be"=(0.96-x)` `"Total number of CATION, "=2x+3(0.96-x)` `=2x+2.88-3x` `=(-x)+2.88` `"Number of anions "O^(2-)=(-2)xx1=-2` `"Number of cations "="Number of anions"` `-x+2.88=2` `-x=-2.88+2` `x=0.88` `%" of Ni as "Ni^(2+)=(0.88)/(0.96)xx100=91.66%` `"Number of "Ni^(3+)" ion will be "=0.96-x` `=0.96-0.88=0.08` `%" of Ni as "Ni^(3+)=(0.08)/(0.96)xx100=8.33%` |
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