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Explain about the hydrolysis of salt of strong acid and a strong base with a suitable example. |
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Answer» Solution :(i) Let us consider the neutralisation reaction between NAOH and `HNO_3` to give water `NaOH(aq) +HNO_3(aq) to NaNO_3 (aq)+H_2O_l` (ii) The salt `NaNO_3` completely dissociated in water to produce `Na^(+) and NO_3^(-)` ions `NaNO_(aq) to^(H_2O) Na^(+) (aq) +NO_3^(-) (aq)` (iii) water dissociates to a small extent as `H_2O_l leftrightarrow H^(+) (aq)+OH^(-) (aq)` Since `[H^+]=[OH^-]` water is neutral. (iv) `NO_3^(-)` ion is the conjugate base of strong acid `HNO_3` and HENCE it has no tendency to react with `H^+` (V) Similarly `Na^+` is the conjugate acid of the strong base NaOh and it has no tendency to react with `Oh^-` (vi) It means that there is no hydrolysis, In such case `[H^+]=[OH^-]`, ph is MAINTAINED and there fore the solution is neutral. |
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