Saved Bookmarks
| 1. |
Explain about the oxidation state of Lanthanoids. |
|
Answer» SOLUTION :(i) The common oxidation state of lanthanoids is +3. In addition to that some of the lanthanoids ALSO show either +2 or +4 oxidation states. (ii) `Gd^(3+)` and `Lu^(3+)` ions have extra stability, it is due to half filled and completely filled f-orbitals. (III) Cerium and terbium attain `4f^(7)` and `4f^(14)` configurations respectively in the +4 oxidation states. (iv) `Eu^(2+)` and `Yb^(2+)` ions have exactly half filled and completely filled f orbitals. (v) Lu shows only +3 oxidation state. (vi) Ce, Pr, Nd, Tb and Dy EXHIBIT +3 and +4 oxidation states. (vii) Nd, Sm, Eu, Tm, Yb exhibit +2 oxidation states also. |
|